问题描述
我试图更新Grub所以我运行:
sudo update-grub
Generating grub configuration file ...
Warning: Setting GRUB_TIMEOUT to a non-zero value when GRUB_HIDDEN_TIMEOUT is set is no longer supported.
这个警告究竟想要改变什么? (我之前从12.04升级到14.04)
这是我的/etc/default/grub
文件:
GRUB_DEFAULT="0"
GRUB_HIDDEN_TIMEOUT="0"
GRUB_HIDDEN_TIMEOUT_QUIET="true"
GRUB_TIMEOUT="10"
GRUB_DISTRIBUTOR="`lsb_release -i -s 2> /dev/null || echo Debian`"
GRUB_CMDLINE_LINUX_DEFAULT="quiet splash"
GRUB_CMDLINE_LINUX=""
最佳解决思路
您不能同时使用GRUB_HIDDEN_TIMEOUT
设置和GRUB_TIMEOUT
设置。即使隐藏超时设置为0也是如此。
您可以注释掉您不想要的行。
例如:
#GRUB_HIDDEN_TIMEOUT=0
保存更改后,再次运行sudo update-grub
。
次佳解决思路
简短回答:
#GRUB_HIDDEN_TIMEOUT=0
#GRUB_HIDDEN_TIMEOUT_QUIET=true
GRUB_TIMEOUT_STYLE=hidden
或者只删除上面条目中的前两行并替换为
GRUB_TIMEOUT_STYLE=[menu|countdown|hidden]
说明:
截至目前(2016年),GRUB_HIDDEN_TIMEOUT
和GRUB_HIDDEN_TIMEOUT_QUIET
选项已被弃用。所以不要再使用它们了。相反,您可以使用GRUB_TIMEOUT_STYLE
。
根据info -f grub -n 'Simple configuration'
,你有这个:
'GRUB_TIMEOUT_STYLE'
If this option is unset or set to 'menu', then GRUB will display
the menu and then wait for the timeout set by 'GRUB_TIMEOUT' to
expire before booting the default entry. Pressing a key interrupts
the timeout.
If this option is set to 'countdown' or 'hidden', then, before
displaying the menu, GRUB will wait for the timeout set by
'GRUB_TIMEOUT' to expire. If <ESC> is pressed during that time, it
will display the menu and wait for input. If a hotkey associated
with a menu entry is pressed, it will boot the associated menu
entry immediately. If the timeout expires before either of these
happens, it will boot the default entry. In the 'countdown' case,
it will show a one-line indication of the remaining time.